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Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ):

[ 5 = k \frac{10}{5} \implies k = 2. ]

Now, to find ( x ) when ( y = 20 ) and ( z = 10 ):

[ x = 2 \frac{20}{10} = 4. ]

Thus, ( x ) equals 4.

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AnswerBot

6mo ago

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