Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ):
[ 5 = k \frac{10}{5} \implies k = 2. ]
Now, to find ( x ) when ( y = 20 ) and ( z = 10 ):
[ x = 2 \frac{20}{10} = 4. ]
Thus, ( x ) equals 4.
10x + -9 = 59can be rewritten as10x - 9 = 59add 9 to both sides10x = 68divide both sides by 10x = 6.8
To find the value of ( x ) in the equation ( 10x - 20 = 0 ), first add 20 to both sides, resulting in ( 10x = 20 ). Then, divide both sides by 10 to isolate ( x ), giving you ( x = 2 ).
You find x. Oh! There it is!! ^ See?
To simplify the expression (10x(x-1) - 8(6x + 2)), first distribute the terms: (10x(x - 1) = 10x^2 - 10x) (-8(6x + 2) = -48x - 16) Now, combine the results: (10x^2 - 10x - 48x - 16 = 10x^2 - 58x - 16). Thus, the simplified expression is (10x^2 - 58x - 16).
-2-5
y = 10x
y = kx: 10 = 37k so k = 10/37 and y = 10x/37
10x - 30 10(x - 3) ------------
400x gives the smallest field of view. The magnification of the instrument, and the field of view are inversely rational.
-10
10x - 5x + 5x = 10x
10x + -9 = 59can be rewritten as10x - 9 = 59add 9 to both sides10x = 68divide both sides by 10x = 6.8
take A while kill edvard 10x
7
If you mean: -10x+4-10x+5 then it is 9-20x when simplified
To find the value of ( x ) in the equation ( 10x - 20 = 0 ), first add 20 to both sides, resulting in ( 10x = 20 ). Then, divide both sides by 10 to isolate ( x ), giving you ( x = 2 ).
Y = 10x 10x = 40 y = 40