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How do you write the sum of 11 and K?
11 + k
What is the sum of 11 and k?
That depends on the value assigned to the variable "k". If you don't know the value of "k", you express the sum as 11 + k; in this case, you can't simplify it any more.
What is the sum of k and twelve?
k12
The sum of 9 and k minus 17?
(9+k)-17=x
One hundred divided by the sum of k and m?
100/(k+m)Its actual value depends on the values of 'k' and 'm' .
How do you write the sum of all even numbers from 2-15 using D O Until Loop?
17
What is the Sum of natural even numbers?
The sum of the even numbers up to 2k, where k is an integer, is k(k + 1) = k2 + k
Flowchart to read 10 positive integers?
The flowchart to read 10 positive integers K>10 Start A N K=1 Sum = 0 Sum = Sum + K2 B Is Y Print K > 100? sum K=k+1 End B A
How do you write the sum of 11 and K?
11 + k
The sum of a number k and 7?
k + 7
1 plus 3 plus 5 plus 7n how will you do this program?
Print "Type the upper limit (n) ?" Input n K = -1 WHILE K < = n K = K + 2 Sum = Sum + K WEND Print "The sum of all odd numbers up to "; n; "is "; Sum
Algorithm for to find sum of individual digits of a positive integer?
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
How do you write a C-program for matrix multiplication?
it would have a part in it like this: for (i=0; i<n; ++i) { . for (j=0; j<l; ++j) { . . sum= 0; . . for (k=0; k<m; ++k) { . . . sum += a[i][k] * b[k][j]; . . } . . c[i][j] = sum; . } }
What is twice the sum of k and 4?
2(k+4)
What is the sum of k squared and k?
k^2 + k = k^2 + k k^2 x k = k^3
What is the sum of 11 and k?
That depends on the value assigned to the variable "k". If you don't know the value of "k", you express the sum as 11 + k; in this case, you can't simplify it any more.
How to Derive variance of Poisson distribution?
If X has the Poisson distribution with mean l then Pr(X = k) = e-llk/k! Mean of Poisson = Sum over all k of [k*P(X = k)] which happens to be l. = Sum over all k of [k*e-llk/k!] = Sum over all k of [e-llk/(k-1)!] = Sum over all j of [le-llj/j!] where j has been substituted for k-1 = l*Sum over all j of [e-llj/j!] But the quantity being summed is simply the pdf of the Poisson distribution and so its sum over all possible values is 1 So Mean = l And then Variance of Poisson = Sum over all k of [k2*P(X = k)] - l2. = Sum over all k of [k2*e-llk/k!] - l2 Then, since k2 = k*(k-1) + k Variance = Sum over all k of [k*(k-1)e-llk/k!] +Sum over all k of [k*e-llk/k!] - l2 = Sum over all j of [l2e-llj/j!] where j has been substituted for k-2 + Sum over all i of [le-lli/i!] where i has been substituted for k-1 - l2 = l2*Sum over all j of [e-llj/j!] + l*Sum over all i of [e-lli/i!] - l2 And since the sums are equal to 1, Variance = l2 + l - l2 = l Apologies: I did the answer using the symbol for lambda but this browser changed them all back to l. I cannot change them all t o something else but I hope it is clear. At least they are distinguishable from 1!
