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What else can I help you with?
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What do you call the number that is multiplied by itself 4 times?
The number that is multiplied by itself 4 times is called the fourth power of that number. In mathematical terms, this is denoted as "n^4" where "n" is the base number. When a number is raised to the fourth power, it is multiplied by itself four times, resulting in the number multiplied by itself four times.
The sum of 3 times m and n?
the sum of 3 times m and n
Real life examples of negative times negative is positive.?
any negative number -n can be written as -1*n (minus 1 times that number). so, multiplying two negative numbers together:-n * -m = -1*n * -1*m = -1*-1*n*m = n*m (which is always positive)-6*-9 = -1*-1*6*9 = 6*9 = 54
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
What is the fourth index law?
It is not possible to answer the question because different books number number the laws differently.
What do you call the number that is multiplied by itself 4 times?
The number that is multiplied by itself 4 times is called the fourth power of that number. In mathematical terms, this is denoted as "n^4" where "n" is the base number. When a number is raised to the fourth power, it is multiplied by itself four times, resulting in the number multiplied by itself four times.
The sum of 3 times m and n?
the sum of 3 times m and n
What do they mean by a to the b power times a to the c power equals a b c power?
ab*ac=ab+c consider the powers of 2. 22=4, 23=8, 22*23=32=23+2=25 when multiplying a number by itself, you raise its power by one. when multiplying a number by itself n times, you raise it to the power of n, so if you raise a number to the power n, then the seame number to the power m, then multiply these together you are multiplying n+m times
What are m and n when 4 over n times 9 times 2 over 9 whole thing powered n minus 2 times x power 6 minus 2n equals m over x power 2?
[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!
What is the power of a matrix?
If n is a natural number and M is a matrix, then Mn denotes the matrix M multiplied by itself n times. We can include n=0, but that is just the identity matrix. So the power of a matrix is very similar to the exponents that are used for numbers.
Why is 4 to the power 0 equal to 1?
for any non zero no. x, x^0=1 the proof is as follows, consider the two no.s x^m and x^n,where m and n are two non zero no.s. now let us assume without any oss of generality,that m>n,hence (x^m)/x^n=(x*x*x....m times)/(x*x*x...n times) now on the r.h.s, n no. of x in the denominator will cancel out n no. of x in the numerator(as x is non zero);leaving (m-n) no. of x in the numerator, i.e. (x^m)/(x^n)=x^(m-n) now letting m=n,we have x^m/x^m=x^(m-m) or, 1=x^0 hence the proof if x is also 0,i.e. 0 to the power 0 is undefined!
M times N equals 6300 if m and n are 2 digit multiples of 10 what could m and n be?
m and n are 70 and 90
