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The formula is A=1/2bh b=base of triangle h=height of triangle A=area 1/2=divide base times height by 2

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Q: What is method of finding a triangles area?
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Why is that if 2 triangles have the same base they have the same area?

Only if the two triangles have the same base and height then they have the same area, because an area of a triangle OS the base times the height divided by two.


What is the formula for finding the area of an ellipse?

the formula for finding the area of an ellipse is add it then multiply and subtract that is the final


How do you find the area of a shape with uneven side's?

There are basically two techniques for finding the area of a shape with uneven or irregularly shaped sides. If the sides can be described by algebraic equations, then integral calculus can be used to find the area. Failing that, you can approximate the irregular shape by fitting in a number of smaller, regularly shaped polygons such as squares and triangles, whose area can be calculated by simple geometric techniques.


Show that the diagonals of parallelogram divide it into four triangles of equal area?

We know that diagonals of parallelogram bisect each other. Therefore, O is the mid-point of AC and BD. BO is the median in ΔABC. Therefore, it will divide it into two triangles of equal areas. Area (ΔAOB) = Area (ΔBOC) ... (1) In ΔBCD, CO is the median. Area (ΔBOC) = Area (ΔCOD) ... (2) Similarly, Area (ΔCOD) = Area (ΔAOD) ... (3) From equations (1), (2), and (3), we obtain Area (ΔAOB) = Area (ΔBOC) = Area (ΔCOD) = Area (ΔAOD) Therefore, it is evident that the diagonals of a parallelogram divide it into four triangles of equal area.


What do you called sss sas asa saa?

they are all postulates or shortcuts on finding 2 triangles congruence, except that SAA does not exist.

Related questions

What are two methods to finding the area of a rectangle?

1 method is to multiply length times the width and the 2 method is to divide the rectangle into triangles and find the area of one of the triangles and multiply the area by two.


When you are finding the area of a triangle do you do the same for all types of triangles?

yes. When you are finding the area of a triangle you do the same for all types of triangles.


What is the formula for finding the area of triangles?

half of the base multipled by the height


Rules of parameterarea in math for 7th class?

Do you mean "perimeter" and "Area"? If so, if you are finding the perimeter of a figure, you take the lengths of all of the sides and add them up. If you are finding area, the method of which you find the area of the figure depends on what the figure is. For quadrilaterals, the formula is: A=lw.(Area=length times width) For triangles, the formula is: A=1/2lw. (Area=One half length times width)


How do you get area of an octagon?

The easiest method is to split the octagon up into triangles and sum the areas of the triangles.


How are the areas Of Triangles Rectangles And Parallelograms Related?

The area of a parallelogram is twice that of the two triangles that are formed by the line transecting it. (Sort of like finding out how many cows you have by counting eyes and dividing by two.)


What is the formula for finding the surface area of a hexagon?

Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude


What is the Practical application for finding the number of diagonals in a regular polygon?

The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.


How can you prove the accuracy of finding the area of a torn-off scrap of paper?

Through a careful study of the method used to estimate the area.


How do you find the area of an uneven shape?

One method is to divide it into regular shapes - rectangles, triangles, etc. - and measure the areas of those shapes.


Method for finding solution to problems?

Experiments are a method for finding solutions to problems.


What is the solution in finding the ratio of similitude for similar triangles?

I am not sure what this is?