The formula is A=1/2bh b=base of triangle h=height of triangle A=area 1/2=divide base times height by 2
Only if the two triangles have the same base and height then they have the same area, because an area of a triangle OS the base times the height divided by two.
the formula for finding the area of an ellipse is add it then multiply and subtract that is the final
Grace Abounds
you use base times height divided by 2
Area = Length x Width
1 method is to multiply length times the width and the 2 method is to divide the rectangle into triangles and find the area of one of the triangles and multiply the area by two.
yes. When you are finding the area of a triangle you do the same for all types of triangles.
half of the base multipled by the height
The easiest method is to split the octagon up into triangles and sum the areas of the triangles.
Do you mean "perimeter" and "Area"? If so, if you are finding the perimeter of a figure, you take the lengths of all of the sides and add them up. If you are finding area, the method of which you find the area of the figure depends on what the figure is. For quadrilaterals, the formula is: A=lw.(Area=length times width) For triangles, the formula is: A=1/2lw. (Area=One half length times width)
The area of a parallelogram is twice that of the two triangles that are formed by the line transecting it. (Sort of like finding out how many cows you have by counting eyes and dividing by two.)
Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude
Experiments are a method for finding solutions to problems.
Through a careful study of the method used to estimate the area.
divide the trapesium into a rectangle and two triangles if you can find the area of triangles
four probe method avoides the necessity of finding cross sectional area of a given material but in two probe method we must first find the crossectional area of material.
One method is to divide it into regular shapes - rectangles, triangles, etc. - and measure the areas of those shapes.