Only if the two triangles have the same base and height then they have the same area, because an area of a triangle OS the base times the height divided by two.
the formula for finding the area of an ellipse is add it then multiply and subtract that is the final
There are basically two techniques for finding the area of a shape with uneven or irregularly shaped sides. If the sides can be described by algebraic equations, then integral calculus can be used to find the area. Failing that, you can approximate the irregular shape by fitting in a number of smaller, regularly shaped polygons such as squares and triangles, whose area can be calculated by simple geometric techniques.
We know that diagonals of parallelogram bisect each other. Therefore, O is the mid-point of AC and BD. BO is the median in ΔABC. Therefore, it will divide it into two triangles of equal areas. Area (ΔAOB) = Area (ΔBOC) ... (1) In ΔBCD, CO is the median. Area (ΔBOC) = Area (ΔCOD) ... (2) Similarly, Area (ΔCOD) = Area (ΔAOD) ... (3) From equations (1), (2), and (3), we obtain Area (ΔAOB) = Area (ΔBOC) = Area (ΔCOD) = Area (ΔAOD) Therefore, it is evident that the diagonals of a parallelogram divide it into four triangles of equal area.
they are all postulates or shortcuts on finding 2 triangles congruence, except that SAA does not exist.
1 method is to multiply length times the width and the 2 method is to divide the rectangle into triangles and find the area of one of the triangles and multiply the area by two.
yes. When you are finding the area of a triangle you do the same for all types of triangles.
half of the base multipled by the height
Do you mean "perimeter" and "Area"? If so, if you are finding the perimeter of a figure, you take the lengths of all of the sides and add them up. If you are finding area, the method of which you find the area of the figure depends on what the figure is. For quadrilaterals, the formula is: A=lw.(Area=length times width) For triangles, the formula is: A=1/2lw. (Area=One half length times width)
The easiest method is to split the octagon up into triangles and sum the areas of the triangles.
The area of a parallelogram is twice that of the two triangles that are formed by the line transecting it. (Sort of like finding out how many cows you have by counting eyes and dividing by two.)
Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
One method is to divide it into regular shapes - rectangles, triangles, etc. - and measure the areas of those shapes.
Through a careful study of the method used to estimate the area.
Experiments are a method for finding solutions to problems.
I am not sure what this is?