The nth triangular number is 0.5*n*(n+1)
t(n) = n*(n+1)/2
The Nth term formula for oblong numbers is N = N(N+1)
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
The nth term is 0.37n+0.5 and the 10th term is 4.2
The nth triangular number is 0.5*n*(n+1)
The sum of the first n cubed numbers is the square of the nth triangular number.
One relationship is that the sum of the nth and the previous triangular numbers is equal to the nth square number.That isT(n-1) + T(n) = S(n)where T(n) is the nth triangular number and S(n) is the nth square number.
0.5n(n+1)
t(n) = n*(n+1)/2
The Nth term formula for oblong numbers is N = N(N+1)
At least two or more numbers are needed to work out the nth term
The Nth triangular number is calculated by: N(N + 1) -------- 2 Hope this is useful!
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
The nth term is 0.37n+0.5 and the 10th term is 4.2
They are: nth term = 6n-4 and the 14th term is 80
it is 6n