PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
You cannot calculate pi with a radius, but pi as a constant is 3.14159265358979323846, and continues on as an irrational number. If you are trying to calculate the area of a circle, the formula is pi X R squared. If R = 5, the the are is 25 X pi.<br><p></p><p> </p>
By guessing, the probability of getting at least 6 correct is 62201/9765625 which is approx 0.0064 or 0.64 % Using the binomial theorem of: (p + q)^n = Σ nCr p^r q^(n-r) with r = 0, 1, ..., n Each term gives the probability of r successes P(r) out of n trials: p is the probability of success and q = 1 - p is the probability of failure for each trial; for this question: p = 1/5 q = 4/5 n = 10 and to get the probability of at least 6, P(≥ 6) is the sum P(6) + P(7) + P(8) + P(9) + P(10) which is: 10C6 p^6 q^4 + 10C7 p^7 q^3 + 10C8 p^8 q^2 + 10C9 p^9 q^1 + 10C10 p^10 q^0 = 210 x (1/5)^6 x (4/5)^4 + 120 x (1/5)^7 x (4/5)^3 + 45 x (1/5)^8 x (4/5)^2 + 10 x (1/5)^9 x (4/5)^1 + 1 x (1/5)^10 x (4/5)^0 = (210 x 1^5 x 4^4 + 120 x 1^7 x 4^3 + 45 x 1^8 x 4^2 + 10 x 1^9 x 4 + 1 x 1^10) x (1/5)^10 = 62201/9765625 ≈ 0.0064 = 0.64 %
If P varies jointly as q, r and s - assume this is in direct proportion, then P ∝ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105
" 5(p+r) " is.
PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
You cannot calculate pi with a radius, but pi as a constant is 3.14159265358979323846, and continues on as an irrational number. If you are trying to calculate the area of a circle, the formula is pi X R squared. If R = 5, the the are is 25 X pi.<br><p></p><p> </p>
the sum of p and r is p + r5 times this sum is 5 × (p + r) = 5(p + r)Multiplication is not written as it looks like an 'x' - it is implied by two things next to each other.The brackets are needed as the addition needs to be done before the multiplication.
P=B×RB=P÷RR=P÷B
By guessing, the probability of getting at least 6 correct is 62201/9765625 which is approx 0.0064 or 0.64 % Using the binomial theorem of: (p + q)^n = Σ nCr p^r q^(n-r) with r = 0, 1, ..., n Each term gives the probability of r successes P(r) out of n trials: p is the probability of success and q = 1 - p is the probability of failure for each trial; for this question: p = 1/5 q = 4/5 n = 10 and to get the probability of at least 6, P(≥ 6) is the sum P(6) + P(7) + P(8) + P(9) + P(10) which is: 10C6 p^6 q^4 + 10C7 p^7 q^3 + 10C8 p^8 q^2 + 10C9 p^9 q^1 + 10C10 p^10 q^0 = 210 x (1/5)^6 x (4/5)^4 + 120 x (1/5)^7 x (4/5)^3 + 45 x (1/5)^8 x (4/5)^2 + 10 x (1/5)^9 x (4/5)^1 + 1 x (1/5)^10 x (4/5)^0 = (210 x 1^5 x 4^4 + 120 x 1^7 x 4^3 + 45 x 1^8 x 4^2 + 10 x 1^9 x 4 + 1 x 1^10) x (1/5)^10 = 62201/9765625 ≈ 0.0064 = 0.64 %
If P varies jointly as q, r and s - assume this is in direct proportion, then P ∝ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105
1/p=x/5 x=5/p so 5/p pages 1/p=x/5 x=5/p so 5/p pages
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1
A polynomial can be factored if it has a rational root. If f(x) is a polynomial function of x and if there is a rational number p such that f(p) = 0 then f(x) = (x-p)*g(x) where g(x) is a polynomial whose order is one less than the order of f(x). If p = q/r where q and r are integers, then (x - p) = (x - q/r) = (rx - q)/r which is a rational binomial factor. This does not work if p is irrational which is why p must be rational.
" 5(p+r) " is.
it is fifth root of 2 = exp (log 2)/5) = 1.1487 = 14.87% The above applies to Compound Interest: At Simple Interest I = PTR/100. In this case I = P, T = 5 and R is unknown. 100 x I = I x 5 x R ie 100 = 5 x R so R = 20%