A polynomial can be factored if it has a rational root.
If f(x) is a polynomial function of x and if there is a rational number p such that f(p) = 0 then
f(x) = (x-p)*g(x) where g(x) is a polynomial whose order is one less than the order of f(x).
If p = q/r where q and r are integers, then
(x - p) = (x - q/r) = (rx - q)/r which is a rational binomial factor. This does not work if p is irrational which is why p must be rational.
Not into rational factors.
Descartes did not invent polynomials.
That would be (x - 2) ( x - 5) ( x - 5). If you like, you can multiply these polynomials to get a single polynomial in standard form (i.e., not factored).
Multiply the first and last coefficients.2*3=6What two factors give you six but when combined give you -5-2 and -3Therefore2x-3)(x-1) will be the factored model.
Reciprocal polynomials come with a number of connections with their original polynomials
Not into rational factors.
A strategy that would be appropriate in factoring polynomials with 4 terms would be by grouping where you first determine if the polynomial can be factored by a group.
Other polynomials of the same, or lower, order.
they have variable
Reducible polynomials.
P. K. Suetin has written: 'Polynomials orthogonal over a region and Bieberbach polynomials' -- subject(s): Orthogonal polynomials 'Series of Faber polynomials' -- subject(s): Polynomials, Series
In mathematics, Jacobi polynomials (occasionally called hypergeometric polynomials) are a class of classical orthogonal polynomials.
what is the prosses to multiply polynomials
Descartes did not invent polynomials.
That would be (x - 2) ( x - 5) ( x - 5). If you like, you can multiply these polynomials to get a single polynomial in standard form (i.e., not factored).
how alike the polynomial and non polynomial
Multiply the first and last coefficients.2*3=6What two factors give you six but when combined give you -5-2 and -3Therefore2x-3)(x-1) will be the factored model.