cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2
If pi=3.1416, then 6×3.1416=18.8416
2 pi / 2 = pi.
(pi/2)-1 = 2/pi
The 42nd digit of pi is 6. (The first 43 digits of pi are 3.141592653589793238462643383279502884197169. If pi were rounded to the nearest 42 digits, then the 6 would be rounded up to a seven.)
cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2
pi squared
It is 2*sqrt(3)/3.
Use the distributive property: 17pi/6 - 2pi = (17/6 - 2) pi. Now, just subtract the fractions as you normally would.
The circumference is: 6*pi/pi = 6 units
If pi=3.1416, then 6×3.1416=18.8416
30 degrees or pi/6
diameter = 2 Pi R = 6 ft so R=diameter/(2 pi) area = Pi R² = Pi x diameter²/(2² pi²)=6²/(4 pi)
Circumference = 2(pi)r OR (pi)d Taking (pi)d = 6 d=6/(pi) d=1.91 (3 significant figures)
Is the radius 6ft? If so, then area = pi*r^2 = pi * (6)^2 = 36 * pi If the diameter is 6ft, then area = pi * (6/2) ^2 = 9 * pi
Since circumference equals pi times the diameter, if the diameter of a circle is 6, then its circumference is going to be pi times 6 or 6 pi.
2 pi / 2 = pi.