24 x 31 x 231
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11.04 = 1104/100 = 1104÷4/100÷4 = 276/25
276 x 4 = 1104 693 + 1104 = 1797
256 (base 10) = 1104 (base 6)
To answer this question, you first need to find all the unique sets of 4 numbers that add up to 6. These are: 0006 0051 0042 0033 0411 0321 0222 3111 2211 Now we need to find which of these can be ordered to give numbers between 1111 and 9999: 0006: 6000 0051: 1500, 5001, 5010, 5100 0042: 2004, 2040, 2400, 4002, 4020, 4200 0033: 3003, 3030, 3300 0411: 1104, 1140, 1401, 1410, 4011, 4101, 4110 0321: 1203, 1230, 1302, 1320, 2013, 2031, 2103, 2130, 2301, 2310, 3012, 3021, 3102, 3120, 3201, 3210 0222: 2022, 2202, 2220 3111: 1113, 1131, 1311, 3111 2211: 1122, 1212, 1221, 2112, 2121, 2211 These are all the numbers between 1111 and 9999 with a digit sum of 6.
12 and 16 go into all their common factors which are multiples of their lowest common factor which is 48. So 12 and 16 both go into:48, 96, 144, 192, 240, 288, 336, 384, 432, 480, 528, 576, 624, 672, 720, 768, 816, 864, 912, 960, 1008, 1056, 1104, 1152, 1200, 1248, 1296, 1344, 1392, 1440, 1488, 1536, 1584, 1632, 1680, 1728, 1776, 1824, 1872, 1920, 1968, 2016, 2064, 2112, 2160, 2208, 2256, 2304, 2352, 2400, 2448, 2496, 2544, 2592, 2640, 2688, 2736, 2784, 2832, 2880, 2928, 2976, 3024, 3072, 3120, 3168, 3216, 3264, 3312, 3360, 3408, 3456, 3504, 3552, 3600, 3648, 3696, 3744, 3792, 3840, 3888, 3936, 3984, 4032, 4080, 4128, 4176, 4224, 4272, 4320, 4368, 4416, 4464, 4512, 4560, 4608, 4656, 4704, 4752, 4800, ...The LCM of 12 and 16 is 48