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Q: What is product of two binomials?

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distributive

(a-b) (a+b) = a2+b2

multiply the 1st term with whole bracket and the 2nd term with whole bracket

no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?

The ones that are the sum or the difference of two terms.

Related questions

a²-b²

distributive.

distributive

the two consecutive positive integers whose product is 380 19 20

(a-b) (a+b) = a2+b2

no please give me 5 riddles about product of 2 binomial

multiply the 1st term with whole bracket and the 2nd term with whole bracket

It means that the question has been written by someone who does not know what the word "polynomial" means, or else that this is a copy-and-paste by someone who knows even less! Only a trinomial can be written as a product of two binomials. No polynomial of any other order can!

Explain how I would use algebra times to multiply two binomials (FOIL)?

no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?

No. A counter-example proves the falsity: Consider the two binomials (x + 2) and (x - 2). Then (x + 2)(x - 2) = x2 - 2x + 2x - 4 = x2 - 4 another binomial.

The two binomials can be written as (x - a)(x + a), for any constant a. Proof: Expand using FOIL: (x - a)(x + a) = x2 + xa - xa - a2 Group: (x - a)(x + a) = x2 - a2 x2 - a2 is a difference of squares. Thus, the product of (x - a) and (x + a) is a difference of squares.

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