It is a fixed number, in an equation, for example, that can be expressed as a ratio of two integers.
If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
Rational
1.14 is rational.
TRue
Rational.
It isn't always possible to determine. For example, it is unknown whether the Euler-Mascheroni constant (0.5772156649...) is rational or irrational.Most famous numbers and constants are known to be rational or irrational. If it can be expressed as a fraction a/b where a and b are integers, it's rational.
The digits of pi are not periodic. Pi is an irrational constant, and if its digits were periodic, it could be expressed as a ratio of constant integers, meaning it would be rational.
No, 3.1415926536 is not rational because it is a rounded representation of the mathematical constant π (pi), which is an irrational number. Irrational numbers cannot be expressed as a fraction of two integers, and π has an infinite, non-repeating decimal expansion. Therefore, while 3.1415926536 may appear to be a rational number, its true nature as a representation of π means it is not rational.
If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
Yes, ( \frac{2x}{3} ) is a rational function. A rational function is defined as the ratio of two polynomials, and in this case, the numerator ( 2x ) is a polynomial of degree 1, while the denominator ( 3 ) is a constant polynomial (degree 0). Since both the numerator and denominator are polynomials, ( \frac{2x}{3} ) qualifies as a rational function.
To find the possible rational zeros of the polynomial ( f(x) = x^3 + 8x + 6 ), we can use the Rational Root Theorem. The possible rational zeros are given by the factors of the constant term (6) over the factors of the leading coefficient (1). Therefore, the possible rational zeros are ( \pm 1, \pm 2, \pm 3, \pm 6 ).
Yes, a polynomial can have no rational zeros while still having real zeros. This occurs, for example, in the case of a polynomial like (x^2 - 2), which has real zeros ((\sqrt{2}) and (-\sqrt{2})) but no rational zeros. According to the Rational Root Theorem, any rational root must be a factor of the constant term, and if none exist among the possible candidates, the polynomial can still have irrational real roots.
No. 1/sqrt(9) can be definitively written as 1/3, which is a ratio of constant numbers, and therefore it is a rational number. A number such as pi, which is irrational, cannot be expressed as a constant ratio.
Rational
1.14 is rational.
In algebra, the rational root theorem (or rational root test, rational zero theorem or rational zero test) states a constraint on rational solutions (or roots) of a polynomialequationwith integer coefficients.If a0 and an are nonzero, then each rational solution x, when written as a fraction x = p/q in lowest terms (i.e., the greatest common divisor of p and q is 1), satisfiesp is an integer factor of the constant term a0, andq is an integer factor of the leading coefficient an.The rational root theorem is a special case (for a single linear factor) of Gauss's lemmaon the factorization of polynomials. The integral root theorem is a special case of the rational root theorem if the leading coefficient an = 1.
4.6 is rational.