64º 136º 144º 54º
If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
The four ways to clear the accumulator in the 8085 are...XRA AMVI A,0SUB ALDA {address of a zero}Answered By:KUNAL SINHARead more: What_are_the_4_ways_to_clear_the_accumulator_in_8085_microprocessors
11
55 + 55 = 110 55 - 55 = 0 55 / 55 = 1 55 * 55 = 3025
RST OF TRAP is 24h(hexadecimail) address.
In the 8085, TRAP vectors at 0024H.
The 5.5 in RST 5.5 means that the interrupt vector is located between RST 5 and RST 6.
RST is simply the opcode chosen to represent the Restart instruction.
The lowest priority interrupt in the 8085 microprocessor is INTR, unless you also consider the software interrupts, RST 0 through RST 7, which are even lower.
RIM, SIM, RST, to name three.
The name, RST6.5, was chosen because the interrupt vector lies halfway between RST 6 and RST 7, specifically at address 0034H.
RST 5.5 is level triggered interrupt & maskable also. it can be masked by using SIM intrruction. Vector address of the RST 5.5 interrupt is 002Ch
Because that's how Intel designed the 8085. In addition to the 8080 type interrupt on the INTR pin, Intel chose, for the 8085, to implement four new interrupts, RST 5.5, RST 6.5, RST 7.5, and TRAP, each of which would not require the interrupting device to provide a vector. The naming convention of x.5 was simply in recognition that Intel placed the implicit vector halfway between two other RST vectors. As an example, RST 6.5 is halfway between RST 6 and RST 7. Since RST 6 and RST 5 are eight bytes away from each other, placing RST 6.5 in between would place a limit of four bytes, and four bytes is enough to place a three byte JMP instruction. The decimal and hex addresses of all of the vectors are... RST 0 - 0 - 00H RST 1 - 8 - 08H RST 2 - 16 - 10H RST 3 - 24 - 18H RST 4 - 32 - 20H TRAP - 36 - 24H RST 5 - 40 - 28H RST 5.5 - 44 - 2CH RST 6 - 48 - 30H RST 6.5 - 52 - 34H RST 7 - 56 - 38H RST 7.5 - 60 - 3CH
The 8085 has five interrupts, INTR, RST5.5, RST6.5, RST7.5, and TRAP. It also has eight software interrupts, RST0, RST1, ..., RST7. The INTR interrupt requires a hardware response that is an opcode. Usually, the opcode is either a CALL instruction, in which case the interrupt vector can go anywhere in memory, or it is an RST instruction, in which case the vector is based on a table in low memory. In the case of RST instructions, either directly or via INTR, or the RSTx.5 interrupts, you simply multiply the interrupt number by 8 to get the vector address. The following table presents the vector addresses for all possible interrupts... RST 0 - 00H RST 1 - 08H RST 2 - 10H RST 3 - 18H RST 4 - 20H TRAP - 24H RST 5 - 28H RST5.5 - 2CH RST 6 - 30H RST 6.5 - 34H RST 7 - 38H RST 7.5 - 3CH
RSTn(0-7) is software interrupt & RST(7.5,6.5,5.5) are INTEL's 8085 maskable interrupts their priority is respectively 7.5,6.5,5.5.RSTn.5 is hardware intterrupt and it is controlled by the external pin available on the chip of 8085. it is used to interrupt the microprocessor from its normal execution and tends to execute some ISR(interrupt service routine)
There are 74 instructions in the 8085 microprocessor.