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If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.

Q: What is the length of rt if rs equals 6 and st equals 6 and mo equals 11 and triangle rst equals triangle mno?

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11

The 1st is a right angle triangle and the 2nd is a scalene triangle.

64º 136º 144º 54º

RST 5.5 is an interrupt request pin (pin 9) on the 8085. It is sampled, along with other interrupt requests, one clock cycle before ALE on the falling edge of CLK. When enabled, and having priority, it causes an interrupt vector sequence using the RST 5.5 instruction, going to location 002CH.

I cannot figure out any pattern in the upper and lower cases, but the characters should be UJO.

Related questions

11

48cm

APEX Congruent-SAS

Three triangles are: scalene, which has three sides of different lengths, isosceles, which has two sides with the same length, and equilateral, which has three sides that are all the same length. In the picture, the scalene triangle is triangle RST, the isosceles triangle is triangle XYZ, and the equilateral triangle is triangle ABC. If two sides or more sides of a triangle have a little line on them, then they are the same length. Click on the related link, "Three Triangles", to see them.

That all sides and angles are also equal.

48

48

The 1st is a right angle triangle and the 2nd is a scalene triangle.

Because that's how Intel designed the 8085. In addition to the 8080 type interrupt on the INTR pin, Intel chose, for the 8085, to implement four new interrupts, RST 5.5, RST 6.5, RST 7.5, and TRAP, each of which would not require the interrupting device to provide a vector. The naming convention of x.5 was simply in recognition that Intel placed the implicit vector halfway between two other RST vectors. As an example, RST 6.5 is halfway between RST 6 and RST 7. Since RST 6 and RST 5 are eight bytes away from each other, placing RST 6.5 in between would place a limit of four bytes, and four bytes is enough to place a three byte JMP instruction. The decimal and hex addresses of all of the vectors are... RST 0 - 0 - 00H RST 1 - 8 - 08H RST 2 - 16 - 10H RST 3 - 24 - 18H RST 4 - 32 - 20H TRAP - 36 - 24H RST 5 - 40 - 28H RST 5.5 - 44 - 2CH RST 6 - 48 - 30H RST 6.5 - 52 - 34H RST 7 - 56 - 38H RST 7.5 - 60 - 3CH

The 5.5 in RST 5.5 means that the interrupt vector is located between RST 5 and RST 6.

RST OF TRAP is 24h(hexadecimail) address.

Because this mnemonic stands for RESTART (RST).