104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
1 squared (1x1) +3=4
8 + X SQUARED
Cosine squared theta = 1 + Sine squared theta
104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
If you mean: 10^2 x 2 + 1 I got : 201
1 squared plus 8 squared or 4 squared plus 7 squared
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
1 squared (1x1) +3=4
1 + cot2x = csc2x
1, 2, 10, 11, 12, 20, 21, 22, 100, 101. Remember, the only digits allowed in base 3 are 0, 1 & 2. So to represent nine, we have 100 which is 3 squared. Ten is nine plus one, or three squared plus one --> 101.
8 + X SQUARED
No, they do not.
(2a+1)(a+1)
Cosine squared theta = 1 + Sine squared theta