3 + (100 x 2) = 3 + 200 = 203
To find the first three terms of the sequence defined by the formula 100-3n, you simply substitute n = 1, 2, and 3 into the formula. For n = 1, the first term is 100-3(1) = 100-3 = 97. For n = 2, the second term is 100-3(2) = 100-6 = 94. For n = 3, the third term is 100-3(3) = 100-9 = 91. Therefore, the first three terms of the sequence are 97, 94, and 91.
6
The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.
0.06 is equivalent to 3/50.0.06 * 100/100 = 6/100 or 3/50 in fraction in lowest term
1, 2, 10, 11, 12, 20, 21, 22, 100, 101.
2, 4, 6 3, 6 The LCM of 2 and 3 is 6.
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
100
Yes. The counting numbers are {1, 2, 3, 4, 5, 6, 7, ...}. Any positive whole amount is a counting number.
Just multiply 100 x 4.Or 100 x 3, if you start counting multiples at zero.
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
3/100 is in its simplest form.
If you mean: -4+3+2s = 15 then s = 8
1, 3, 5, 7, 9 counting by twos to 99 are the odd numbers. 2, 4, 6, 8, 10 counting by twos to 100 are the even numbers.
To find the first three terms of the sequence defined by the formula 100-3n, you simply substitute n = 1, 2, and 3 into the formula. For n = 1, the first term is 100-3(1) = 100-3 = 97. For n = 2, the second term is 100-3(2) = 100-6 = 94. For n = 3, the third term is 100-3(3) = 100-9 = 91. Therefore, the first three terms of the sequence are 97, 94, and 91.
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)