The GCF is 1.
m² - 14m + 48 = (m - 6)(m - 8)
237288135.5932203
Area of a rectangle is width times lenght. 14m in lenght (times) 5m in width = 70m2
14m x 8m x 6m = 672 m^3
The GCF is 7m.
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
The GCF is 1.
The greatest common factor (GCF) is 7m.
The GCF is 7mn.
If one term is a factor of the other, it is automatically the GCF. 7m is a factor of 14m and the GCF of this problem.
10-14m = -4
The cast of 21m - m392 - 2011 includes: Jose Dols as 21m m392 Jorge Martija as Uoham2 Natalia Molinos as Uoham1
43km 14m to kilometers
It is: 7m
The LCM of 7m-21 and 14m-42 is 14m-42. Since 14m-42 is a multiple of 7m-21, it is also the least common multiple (LCM) of the two expressions.
m² - 14m + 48 = (m - 6)(m - 8)