3,136 k2 + 2,800 k + 625
The equation for a circle of radius r and centre (h, k) is: (x - h)² + (y - k)² = r² If the centre is the origin, the centre point is (0, 0), thus h = k = 0, and this becomes: x² + y² = r²
All we can deduce from that information is that k is a positive perfect square. Is that really the whole question? What?
-98-4h+8k-40+k-9h = (-98-40)+(-4h-9h)+(8k+k) = -138-13h+9k
40/x
The GCF is 1.
A kilobyte (or a k) is 1024 bytes, so 16k is 16*1024 bytes or 16384 bytes.
If the line y = kx - 2 is a tangent to the curve y = x² - 8x + 7, then where they meet: kx - 2 = x² - 8x + 7 → x² - (8+k)x + 9 = 0 will have a repeated root, ie the determinant is zero: (8+k)² - 4 ×1 × 9 = 0 → 64 + 16k + k² - 36 = 0 → k² + 16k + 28 = 0 → (k + 2)(k + 14) = 0 → k = -2 or -14.
k2 + k2 = 2k2
$16,000. (Sixteen thousand dollars) "K" after a number is an abbreviation for thousand.
3,136 k2 + 2,800 k + 625
k(k + 5)
k^2 + k = k^2 + k k^2 x k = k^3
The algebraic expression for "k squared minus 11" is k ² -11. This can't be solved because it's only an expression not an equation.
k = 0.1
√(40)=k√(10) Isolate k by dividing both sides by √(10) √(40)/√(10)=k √(40/10)=k √(4)=k k=2
Let k = 0 9x18 squared x 17 x 18 k is a constant. Its anti-derivative is kx + C, where C is a constant. The anti-derivative squared is (kx+ C) squared.