K
40 \ x
2/3 x 120 = 80 (Divide 120 by 3 and then multiply the quotient by 2
Let the number be 'x'. Quotient of 80 and x would be : 80/x
The quotient of two numbers, X and Y, is X/Y.
10 < or = to T/4 x4 x 4 cancels out just leaves T 40 < or = to T T < or = to 40
x/5
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.
4 x 1 = 4 (4 / 1 = 4) 4 x 10 = 40 (40 / 4 = 10) Since 18.88 is between 4 and 40, you can conclude that the quotient must be between 1 and 10.
40
40/8 = 5
2/3 x 120 = 80 (Divide 120 by 3 and then multiply the quotient by 2
Let the number be 'x'. Quotient of 80 and x would be : 80/x
the quotient of 7 and x is simply 7x, unless you know what x stands for
The quotient of two numbers, X and Y, is X/Y.
Simply write this as 40/n.
10 < or = to T/4 x4 x 4 cancels out just leaves T 40 < or = to T T < or = to 40
When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?
40/3 = 13.3 recurring (that is, 13.3333...)