40/x
Let the number be 'x'. Quotient of 80 and x would be : 80/x
The quotient of two numbers, X and Y, is X/Y.
40/3 = 13.3 recurring (that is, 13.3333...)
0.0536
Divide 40 by 2, which is the base of binary, and then divide the quotient obtained by 2. Continue the process as long as the quotient obtained in each case is greater than 1.40 = 2 x 20 + 020 = 2 x 10 + 010 = 2 x 5 + 05 = 2 x 2 + 12 = 2 x 1 + 0(We stop here as quotient is 1)Remainder obtained in first step is given the lowest priority and priority goes on increasing with each step.And the binary equivalent is obtained as:Write the quotient obtained in last step followed by the remainder according to the priority: 101000.Thus, binary equivalent is 101000.
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.
The quotient of 40 and 4 is 10. This is calculated by dividing 40 by 4, which results in 10.
4 x 1 = 4 (4 / 1 = 4) 4 x 10 = 40 (40 / 4 = 10) Since 18.88 is between 4 and 40, you can conclude that the quotient must be between 1 and 10.
40/8 = 5
40
what is
the quotient of 7 and x is simply 7x, unless you know what x stands for
Let the number be 'x'. Quotient of 80 and x would be : 80/x
The quotient of two numbers, X and Y, is X/Y.
Simply write this as 40/n.
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?