Oh, dude, you're hitting me with some math vibes here! So, like, the highest common factor (HCF) of 1020 and 11594 by division method is basically finding the largest number that divides both of them without leaving a remainder. You just divide the bigger number by the smaller number until you get a remainder of 0, and that magical number is your HCF. Happy dividing, math wizard!
19 ÷ 6 = 3 r 1 6 ÷ 1 = 6 r 0 → hcf(19, 6) = 1.
Write the numbers next to each other. Now divide all three numbers by any common factor greater than 1 and repeat until no common factor greater than 1 exists. Multiply together the factors by which you divided to get the HCF: ___2__|__1624___552__1276 ___2__|____812___276___638 ______|____406___138___319 No more common factors (other than 1) → hcf(1624, 552, 1276) = 2 × 2 = 4
The Highest Common Factor (HCF) of 225 and 63 is 9. To find the HCF, you can use the prime factorization method. First, find the prime factors of each number: 225 = 3 x 3 x 5 x 5 and 63 = 3 x 3 x 7. Then, identify the common prime factors and multiply them together to get the HCF, which in this case is 3 x 3 = 9.
The highest common factor (HCF) of 160 and 200 is the largest positive integer that divides both 160 and 200 without leaving a remainder. To find the HCF, you can use the prime factorization method. The prime factorization of 160 is 2^5 * 5, and the prime factorization of 200 is 2^3 * 5^2. To find the HCF, you take the common factors with the lowest exponent, which in this case is 2^3 * 5 = 40. Therefore, the HCF of 160 and 200 is 40.
The least common multiple (LCM) of 72 and 252 is the smallest number that is a multiple of both 72 and 252. To find the LCM, we can use the formula LCM(a, b) = (a * b) / HCF(a, b), where a = 72 and b = 252. The highest common factor (HCF) of 72 and 252 is the largest number that divides both 72 and 252 without leaving a remainder. To find the HCF, we can use the Euclidean algorithm or prime factorization method.
Oh, let's paint a happy little picture with numbers! To find the Highest Common Factor (HCF) of 1020 and 11594, we can use the division method. We divide the larger number by the smaller number, then divide the divisor by the remainder until we get a zero remainder. The last divisor before we get a zero remainder is the HCF. So, the HCF of 1020 and 11594 is 34.
To find the highest common factor (HCF) of two numbers using the division method, follow these steps: For 1020 and 11594: Step 1: Divide the larger number by the smaller number. Divide 11594 by 1020: 11594 Γ· 1020 = 11 remainder 414 Step 2: Now, divide the divisor from the previous step (1020) by the remainder obtained (414). 1020 Γ· 414 = 2 remainder 192 Step 3: Repeat the division process with the previous divisor (414) and the new remainder (192). 414 Γ· 192 = 2 remainder 30 Step 4: Continue the process until you obtain a remainder of 0. 192 Γ· 30 = 6 remainder 12 30 Γ· 12 = 2 remainder 6 12 Γ· 6 = 2 remainder 0 Step 5: The last divisor with a remainder of 0 is the HCF of the two numbers. Therefore, the HCF of 1020 and 11594 is 6.
Ans: 1
The GCF of 12 and 20 is 4.
For the division of quantities
hcf(87, 102) = 3. factorization method: 87 = 3 x 29 102 = 2 x 3 x 17 hcf = 3
3
882/2 = 441/3 = 147/3 = 49/7 = 7/7 = 13150/2 = 1575/3 = 525/3 = 175/5 = 35/5 = 7/7 = 12 x 3 x 3 x 7 x 7 = 8822 x 3 x 3 x 5 x 5 x 7 = 31502 x 3 x 3 x 7 = 126, the GCF
1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12
Yes.First find the HCF of two of the numbers, then find the HCF of that answer and the third number.In this way you could find the HCF of as many numbers as you want.
19 ÷ 6 = 3 r 1 6 ÷ 1 = 6 r 0 → hcf(19, 6) = 1.
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF