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What is the hcf of 19 and 6 using the Euclid division algorithm?
19 ÷ 6 = 3 r 1 6 ÷ 1 = 6 r 0 → hcf(19, 6) = 1.
How do you do the HCF of1624 552 1276 by the long division method?
Write the numbers next to each other. Now divide all three numbers by any common factor greater than 1 and repeat until no common factor greater than 1 exists. Multiply together the factors by which you divided to get the HCF: ___2__|__1624___552__1276 ___2__|____812___276___638 ______|____406___138___319 No more common factors (other than 1) → hcf(1624, 552, 1276) = 2 × 2 = 4
What is the HCF of 225 and 63?
The Highest Common Factor (HCF) of 225 and 63 is 9. To find the HCF, you can use the prime factorization method. First, find the prime factors of each number: 225 = 3 x 3 x 5 x 5 and 63 = 3 x 3 x 7. Then, identify the common prime factors and multiply them together to get the HCF, which in this case is 3 x 3 = 9.
What is the HCF of 120 and 65?
The Highest Common Factor (HCF) of 120 and 65 is the largest positive integer that divides both 120 and 65 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 120 is 2^3 * 3 * 5 and the prime factorization of 65 is 5 * 13. The common factors are 5, so the HCF of 120 and 65 is 5.
HCF and LCM of 40 and 55?
HCF = 5LCM = 440
What is the HCF of 1020 and 11594 answer with solution by division method?
To find the Highest Common Factor (HCF) of 1020 and 11594 using the division method, we first divide the larger number, 11594, by the smaller number, 1020. 11594 divided by 1020 gives a quotient of 11 with a remainder of 554. Next, we divide the divisor, 1020, by the remainder, 554. 1020 divided by 554 gives a quotient of 1 with a remainder of 466. Continuing this process, we divide 554 by 466, which gives a quotient of 1 with a remainder of 88. Finally, we divide 466 by 88, which gives a quotient of 5 with a remainder of 46. Since the remainder is not zero, we continue the process. Dividing 88 by 46 gives a quotient of 1 with a remainder of 42. Continuing, we divide 46 by 42, which gives a quotient of 1 with a remainder of 4. Finally, dividing 42 by 4 gives a quotient of 10 with a remainder of 2. Since the remainder is not zero, we continue. Dividing 4 by 2 gives a quotient of 2 with a remainder of 0. Therefore, the HCF of 1020 and 11594 is 2.
please give me the full solution of 1020 and 11594 hcf by division methord?
To find the highest common factor (HCF) of two numbers using the division method, follow these steps: For 1020 and 11594: Step 1: Divide the larger number by the smaller number. Divide 11594 by 1020: 11594 ÷ 1020 = 11 remainder 414 Step 2: Now, divide the divisor from the previous step (1020) by the remainder obtained (414). 1020 ÷ 414 = 2 remainder 192 Step 3: Repeat the division process with the previous divisor (414) and the new remainder (192). 414 ÷ 192 = 2 remainder 30 Step 4: Continue the process until you obtain a remainder of 0. 192 ÷ 30 = 6 remainder 12 30 ÷ 12 = 2 remainder 6 12 ÷ 6 = 2 remainder 0 Step 5: The last divisor with a remainder of 0 is the HCF of the two numbers. Therefore, the HCF of 1020 and 11594 is 6.
Find the HCF of given numbers by division method: 122, 234, 325?
Ans: 1
Hcf of 12 and 20 by division method?
The GCF of 12 and 20 is 4.
Use euclid division algorithm to find HCF of 867 and255?
3
What is the greatest common factor of 87 and 102?
hcf(87, 102) = 3. factorization method: 87 = 3 x 29 102 = 2 x 3 x 17 hcf = 3
What is the HCF of 882 and 3150 using continued division method?
882/2 = 441/3 = 147/3 = 49/7 = 7/7 = 13150/2 = 1575/3 = 525/3 = 175/5 = 35/5 = 7/7 = 12 x 3 x 3 x 7 x 7 = 8822 x 3 x 3 x 5 x 5 x 7 = 31502 x 3 x 3 x 7 = 126, the GCF
HCF by prime factorization by short division method?
1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12
Can you find the HCF of 3 numbers using euclids division lemma?
Yes.First find the HCF of two of the numbers, then find the HCF of that answer and the third number.In this way you could find the HCF of as many numbers as you want.
What is the hcf of 19 and 6 using the Euclid division algorithm?
19 ÷ 6 = 3 r 1 6 ÷ 1 = 6 r 0 → hcf(19, 6) = 1.
HCF of 70 by prime factorization method?
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
How do you do the HCF of1624 552 1276 by the long division method?
Write the numbers next to each other. Now divide all three numbers by any common factor greater than 1 and repeat until no common factor greater than 1 exists. Multiply together the factors by which you divided to get the HCF: ___2__|__1624___552__1276 ___2__|____812___276___638 ______|____406___138___319 No more common factors (other than 1) → hcf(1624, 552, 1276) = 2 × 2 = 4
