The Highest Common Factor (HCF) of 336 and 384 is the largest number that divides both 336 and 384 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number, then using the remainder as the divisor in the next iteration. Continuing this process will eventually lead to a remainder of 0, at which point the divisor will be the HCF. In this case, the HCF of 336 and 384 is 48.
384
336 and 48
Well, well, well, look who's trying to be a math whiz! The LCM of 84 and 96 is 336, and the HCF is 12. So there you have it, now go impress your friends with your newfound knowledge.
1 x 336 = 336 2 x 168 = 336 3 x 112 = 336 4 x 84 = 336 6 x 56 = 336 7 x 48 = 336 8 x 42 = 336 12 x 28 = 336 14 x 24 = 336 16 x 21 = 336
To have a HCF, you need at least 2 numbers. There is no HCF in just 1 number.
The HCF of 108 and 336 is 12
It is: 12
4 and 336, respectively.
LCM = Product/HCF = 384
48 & 336; 144 & 240; For inf, this was calculated by dividing 384 by 48, giving 8. This means that the numbers sought are multiples of 48 by two numbers totalling 8. 1/7 and 3/5 are the only answers which fit the question as 2/6 would mean the HCF was 96 (96 and 288).
The Highest Common Factor (HCF) of 384 and 512 is the largest number that divides both 384 and 512 without leaving a remainder. To find the HCF, we first list the factors of each number: 384 factors are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, and 384. 512 factors are 1, 2, 4, 8, 16, 32, 64, 128, 256, and 512. The largest number that appears in both lists is 64, so the HCF of 384 and 512 is 64.
48, 96, 144, 192, 240, 288, 336, 384, 432, 480, 528, . . .
384
336 and 48
48, 96, 144, 192, 240, 288, 336, 384, 432, 480, 528, . . .
48, 96, 144, 192, 240, 288, 336, 384, 432 . . .
1, 2, 3, 4, 6, 8, 12, 16, 24, 48