To find the LCM, express the numbers in their prime factors using power notation and multiply together the highest power of each prime that is found among the factorisations:
12 = 22 x 31
42 = 21 x 31 x 71
75 = 31 x 52
LCM = 22 x 31 x 52 x 71
= 4 x 3 x 25 x 7
= 2100
0.042 L
The Least Common Multiple of 12 and 8 is 24.
there are 3/3 in a whole, and you need 4 wholes, multiply that and you get 12.
75mL = 0.75L
The area can't exactly be determined here since we don't have enough information about the sides of the rectangles! We only know that the perimeter of the rectangle is 42 cm. Then: P = 2(l + w) where l is the length and w is the width. 42 = 2(l + w) 21 = l + w Solve for either w or l to get... w = 21 - l So by the area of the rectangle, we obtain: A = lw A = l(21 - l) = 21l - l² So we can't really determine the area of the rectangle. It's just the general form of the rectangle with the perimeter 42 cm.
C. L. Dellums died on 1989-12-06.
.75 L
12 countrymen in Lyallpur, city in northeast Pakistan,
75 ml = 0.075 L
W-I-T-C-H- - 2004 L Is for Loser 2-12 was released on: USA: 27 August 2006
0.75 L is greater than 75 mL0.75 L = 750 mL > 75 mL
remember: 1000 mL = 1 L then 75 mL = 0.075 L
We can solve this by taking our basic equations for the perimeter and area of a rectangle: a = lw p = 2(l + w) And then plugging the given values into those: 42 = lw 48 = 2(l + w) Now we can solve one of them for either variable. We'll go with solving the first one for l: l = 42/w And then we can plug that into the other one: 48 = 2(42/w + w) And solve for w: 48 = 2(42/w + w) 48 = 84/w + 2w 48w = 84 + 2w2 2w2 - 48w + 84 = 0 w2 - 24w + 42 = 0 w2 - 24w + 144 = 102 (w - 12)2 = 102 w - 12 = ± √102 w = 12 ± √102 So yes, that is indeed possible, and it's length and width will be 12 - √102 and 12 + √102 (or approximately 1.9005 by 22.0995).
Check the receiver
0.042 L
24 different ways. wow that took a while turkey- TU cheese- C lettuce- L tomato- T Tu, C, L, T Tu, C, T L Tu, L,C,T Tu,L,T,C Tu,C,T,L Tu,C,L,T C,TU,L,T C,TU,T,L C,L,TU,T C,L,T,TU C,T,L,TU C,T,TU,L L,TU,T,C L,TU,C,T L,C,TU,T L,C,T,TU L,T,TU,C L,T,C,TU T,TU,C,L T,TU,L,C T,L,TU,C T,L,C,TU T,C,TU,L T,C,L,TU
Infinitely many. Suppose the length of the rectangle if L feet where L is any number greater than sqrt(42) = approx 6.481 ft. Let the width of the rectangle be W = 42/L feet. Then its area is L*W = L*42/L = 42 sq ft There are infinitely many possible values for L and so infinitely many rectangles.