The area can't exactly be determined here since we don't have enough information about the sides of the rectangles! We only know that the perimeter of the rectangle is 42 cm. Then:
P = 2(l + w) where l is the length and w is the width.
42 = 2(l + w)
21 = l + w
Solve for either w or l to get...
w = 21 - l
So by the area of the rectangle, we obtain:
A = lw
A = l(21 - l)
= 21l - l²
So we can't really determine the area of the rectangle. It's just the general form of the rectangle with the perimeter 42 cm.
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42 inches = 3.5 feet48 inches = 4 feetThe area of a rectangle that measures (42" by 48") is (3.5 x 4) = 14 square feet.
42
Name the length x & the width ythen, x = 5 + 2yknowing that the area of the rectangle is obtained from the multiplication of its length times its width ,then:x * y = 42(5 + 2y)*y = 425y + 2y^2 = 422y^2 + 5y - 42 = 0solving the above equation you'll obtain these two values for x :y = 3.5 which is adopted (as it's a positive value)y = -6 which is rejected as a length due to its minus sign.Now,solve for x:x = 5 + 2yx = 5 + 2(3.5)x = 12Conclusion:The length of the rectangle is equal to 12 feet &its width is equal to 3.5 feet.
The numbers are 41, 42 and 43.
41, 42, 43