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The area can't exactly be determined here since we don't have enough information about the sides of the rectangles! We only know that the perimeter of the rectangle is 42 cm. Then:

P = 2(l + w) where l is the length and w is the width.

42 = 2(l + w)

21 = l + w

Solve for either w or l to get...

w = 21 - l

So by the area of the rectangle, we obtain:

A = lw

A = l(21 - l)

= 21l - l²

So we can't really determine the area of the rectangle. It's just the general form of the rectangle with the perimeter 42 cm.

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12y ago

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Q: What is the area of a rectangle whose perimiter is 42 cm?
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