The line y = 6 is horizontal and has a slope of zero, as does any line that is parallel to it.
9
7/9
4
Slope is found by this form. Y = mX + c ( m = slope ) - 5X - 7Y - 6 = 0 ( I assume this is what you mean ) - 7Y - 6 = 5X - 7Y = 5X + 6 Y = - 5/7X - 6/7 The slope would be in this instance, - 5/7 ----------
-3
2.5
6
To find the slope of the line parallel to the given line, we first need to rewrite the equation in slope-intercept form (y = mx + b). The equation -y = -4x + 6 can be rearranged to y = 4x - 6. The slope (m) of this line is 4. Therefore, the slope of any line parallel to it will also be 4.
-2/3
9
6
y = -7x + 6 is the equation of a straight line. It has a slope of '-7' and a y-intercept of '6'. For it to be parallel it must be compared to another line. e.g. y = -7x + 12 is a paralle line However, y = 7x + 6 is NOT a parallel line, because the slope is in a different direction.
To determine if the line ( y = 3x + 6 ) is perpendicular or parallel to another line, we need to compare their slopes. The slope of this line is 3. Two lines are parallel if they have the same slope, and they are perpendicular if the product of their slopes is -1. Therefore, without another line for comparison, we can't definitively state if it is perpendicular or parallel; we can only say that it has a slope of 3.
Slope is 6.
Put in this form to see. Y = mX + c9X + 3Y = 63Y = - 9X + 6Y = - 3X + 2=========The slope of the line you seek is - 3.
The slope of any line parallel to this line is the same as the slope of the line itself, by the definition of "parallel" 7x + 9y = 6 can be rewritten as y =(6 - 7x)/9. To find the slope of such a line, select two distinct values of x denoted x1 and x2, then calculate the corresponding values y1 and y2. The slope will then be equal to (y2 - y1)/(x2 - x1). For example, if x1 is zero, y1 = 6/9 = 2/3. If x2 is one, y2 = -(1/9). The slope is therefore: (- 1/9 - 2/3)/(1 - 0) = - (7/9).
14