Slope is found by this form. Y = mX + c ( m = slope )
- 5X - 7Y - 6 = 0 ( I assume this is what you mean )
- 7Y - 6 = 5X
- 7Y = 5X + 6
Y = - 5/7X - 6/7
The slope would be in this instance,
- 5/7
----------
Chat with our AI personalities
If you mean 2x-15y 0, then y (-2/15)x and dy/dx -(2/15). If you mean something else, you need to clarify the expression 3y5.
I'm pretty sure that what you're looking for is: Either the slope or the full equationof the line that is tangent to the curve represented by that messy equation, atthe point (1, 1).If that's so, then . . .-- You'd have to start out by knowing where the plus, minus, and 'equals' signsare in the equation.From there, what I would do is:-- Take the implicit first derivative of the equation, and solve it for y' .That gives you the slope of the curve as a function of points (x, y).-- Use it to find the slope of the curve at the point (1, 1).-- You know that the slope of the line that's tangent at that point is thenegative reciprocal of the slope of the curve. Now you have the slope ofthe tangent line. If that's all you need, then you're done. Retreat and declarevictory.-- If you need the equation of the tangent line, that's no problem. You haveits slope AND a point on it ==> (1, 1). Using that info to find the equationof the line is supposed to be a piece o' cake for you by now.=============================Wait. Don't go away.It looks to me as if the equation is3x3 + 7x2y + 7xy2 + 2y3 = 19just because the point (1, 1) is on it.Do not trust anything I say past this point. I have already wasted too much time on this one and I am not going to check my work. But I did differentiate that mess, and I got the following:Slope of the equation at (1, 1) . . . -10/9Slope of the line tangent to the graph at (1, 1) . . . +0.9Equation of the line . . . Y = 0.9x + 0.1Take it for what it's worth, and Good Luck.
If you mean what does an o with a line over it means, it means that there is emphasis on the o. Such as, Rōb would be pronounced like Robe, not Rob. If you mean how to type it, I just searched what is an o with a line over it? in google, then copy and pasted it onto my document. Hope this helped.
The diameter.
1. A given length of line is drawn from points A to B. 2. A compass is used to measure the line and construct an equalateral triangle using line A to B as the base side of the triangle. 3. Use the compass to bisect the two adjacent ventexs at the base of the triangle extending these lines till they intersect finding the center, point O, of the triangle. 4.Draw the solution finding line parallel to A to B through point O. Extend this line to intersect with the sides of the triangle at points C and D. 5. One third of line A to B is equal to line section A to C and line section B to D.