To find 2 times the sum of y and 5, you first need to calculate the sum of y and 5 by adding y and 5 together. Once you have the sum, you then multiply it by 2 to find the final result. The expression for this calculation would be 2(y + 5).
It is: (5+4) times 8 = 72
You multiply 2/5 by 5 so you get 10/25. 10/25 + 11/25= 21/25
Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum
To find 5 times the sum of 7 and 23, you first need to calculate the sum of 7 and 23, which is 30. Then, you multiply this sum by 5 to get the final answer. Therefore, 5 times the sum of 7 and 23 is 5 x 30, which equals 150.
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
12 x 5 = 60
Multiply sum by 2.
5
To find 2 times the sum of y and 5, you first need to calculate the sum of y and 5 by adding y and 5 together. Once you have the sum, you then multiply it by 2 to find the final result. The expression for this calculation would be 2(y + 5).
5 Check the intensity of the object. The sum will be 5.
The answer is 24.
If you mean circumference just multiply 5 by 3.14 and that's your answer :)
It is: (5+4) times 8 = 72
You multiply 2/5 by 5 so you get 10/25. 10/25 + 11/25= 21/25
Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum
solve anything in brackets before anything else. ex: [7+2(9-4)]8 you would do the 7+2 first, (9) then the parenthesis (5) then multiply the 9 and the 5 (45) and then multiply that by 8 (360)