25
Numbering the alphabet backwards from 1-26, Y would be number 2 while B would end up number 25.
the series of odd numbers from 1 to 99 :1 3 5 7 9.....99 SUM OF THE SERIES: It is a geometric progression with a=1 and l=99 and common difference (d)=2. let 99 be the nth term of the sequence so, 99=1+(n-1)d 99=1+(n-1)2 solving this we get n =50. SUM=(n/2)(a+l) =(50/2)(1+99) =(25)(100) =2500.
You're likely to encounter some difficulty proving that statement, because it's false. 2/55 is about 3.6% 6/99 is about 6.1%
(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25
2 x 50 = 100 2 x 49 = 98 99 - 98 = 1 Answer: 49 times with 1 remaining
both numerator and denominator are divisible by 25; 25/50 = 1/2
99
1, 2, 5, 10, 25, 50 1, 3, 9, 11, 33, 99
the series of odd numbers from 1 to 99 :1 3 5 7 9.....99 SUM OF THE SERIES: It is a geometric progression with a=1 and l=99 and common difference (d)=2. let 99 be the nth term of the sequence so, 99=1+(n-1)d 99=1+(n-1)2 solving this we get n =50. SUM=(n/2)(a+l) =(50/2)(1+99) =(25)(100) =2500.
No. 50, 20, 20, 5, 2, 2 will make 99 cents in the Euro zone.
You're likely to encounter some difficulty proving that statement, because it's false. 2/55 is about 3.6% 6/99 is about 6.1%
2-55 2 to 6=4 55+44 is 99 please explain it a detailed way...
1 + 98 or 2 + 97 or 1*99 or 2*49.5 or 100-1 or 101-2 or 99/1 or 198/2 or ... the list is endless.
(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25(1/2) / (2/25) = (1/2) * (25/2) = 25
- 5/2
99
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
√99 = Square root of 99 = Irrational. Rational # are able to be expressed as the ratio of 2 integers. i.e. √25 = +5 5 = 5/1 = rational Irrational # can not be expressed as a ratio of 2 integers.