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What is the exterior angle of a 9 sided polygon?
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
What is the interior angle of a 9 sided polygon?
To find the interior angle of a polygon, you can use the formula: (n-2) * 180 / n, where n is the number of sides. For a 9-sided polygon, the formula would be (9-2) * 180 / 9, which simplifies to 7 * 180 / 9 = 1260 / 9 = 140 degrees. Therefore, the interior angle of a 9-sided polygon is 140 degrees.
What is the number of sides of a regular polygon if one angle measures 140 degrees?
Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.
What is the number of sides of a regular polygon if one angle measures 171 degrees?
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
Each interior angle of a regular polygon is 140 How many sides has the polygon?
Interior angle = 140 deg so exterior angle = 40 deg. Sum of exterior angles = 360 so 360/40 = 9 such angles required. So the figure has 9 sides.
