48
As 8 and 6 are both factors of the number, we want the lowest common multiple of 6 and 8 which is 24. There are at least 24 kids. (The number of kids is a multiple of 24.)
To divide 24 equally, you can use factors of 24, which are 1, 2, 3, 4, 6, 8, 12, and 24. Therefore, you can divide 24 into 1 group of 24, 2 groups of 12, 3 groups of 8, 4 groups of 6, 6 groups of 4, 8 groups of 3, 12 groups of 2, or 24 groups of 1. Each of these divisions results in equal parts of 24.
There are 7.
This is just asking for the factors of 24, due to the fact that any factors of the number would be equal groups. Assuming that this isn't based on the room itself, the combinations would be: 1 group of 24, 2 groups of 12, 3 groups of 8, and 4 groups of 6, due to the fact that the factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24.
48
As 8 and 6 are both factors of the number, we want the lowest common multiple of 6 and 8 which is 24. There are at least 24 kids. (The number of kids is a multiple of 24.)
To divide 24 equally, you can use factors of 24, which are 1, 2, 3, 4, 6, 8, 12, and 24. Therefore, you can divide 24 into 1 group of 24, 2 groups of 12, 3 groups of 8, 4 groups of 6, 6 groups of 4, 8 groups of 3, 12 groups of 2, or 24 groups of 1. Each of these divisions results in equal parts of 24.
To get 48, you could multiply 6 by 8, as 6 x 8 = 48. This is because multiplication is a mathematical operation that combines equal groups together. In this case, you are combining 6 groups of 8 to get a total of 48.
The least number of band members needed to form groups of 4, 5, 6, and 8 is 23.
The answer is 8C6 = 8!/[6!*(8-6)!] where n! = 1*2*3*...*n So, the answer is 28.
here are all the possible combinations 6(12)+8 6(10)+10(2) 6(9)+8(2)+10 6(8)+8(4) 6(7)+8+10(3) 6(6)+8(3)+10(2) 6(5)+8(5)+10 6(5)+10(5) 6(4)+8(2)+10(4) 6(4)+8(7) 6(3)+8(4)+10(3) 6(2)+8+10(6) 6(2)+8(6)+10(2) 6+8(3)+10(5) 6+8(8)+10 8(10) 8(5)+10(4) 10(8)
There are 7.
If the 8 people consist of 6 or more women, the answer is none. If the question is intended to be gender neutral, then the answer is 8*7*6/(3*2*1) = 56
Yes, you can. Normally 6-8 is two groups of three in a bar, but three crotchets gives a cross-rhythm called a hemiola.
The 8 groups of invertebrates are as follows: PoriferaCnidariaNemathelminthesPlatyhelminthesAnnelidaArthropodaMolluscaEchinodermata
24 groups of 8 = 192