2 tens and 13 ones add up to 33 because 10 +10 +13 = 33.
25
3 tens is equal to the number 30, and 3 ones is equal to the number 3.So, 3 tens and 3 ones is 33; and 67 minus 33 (or 67 less33) is 34.You could also look at the number 67 and see that it is 6 tens and 7 ones. Then it is easier to say "6 tens and 7 ones minus 3 tens and 3 ones = 34"because:6 tens minus 3 tens = 3 tens, and 7 ones minus 3 ones = four ones.3 tens and four ones = 34
3,531 = 11 + 220 + 3,300
265.99
2 tens and 13 ones add up to 33 because 10 +10 +13 = 33.
25
3 tens is equal to the number 30, and 3 ones is equal to the number 3.So, 3 tens and 3 ones is 33; and 67 minus 33 (or 67 less33) is 34.You could also look at the number 67 and see that it is 6 tens and 7 ones. Then it is easier to say "6 tens and 7 ones minus 3 tens and 3 ones = 34"because:6 tens minus 3 tens = 3 tens, and 7 ones minus 3 ones = four ones.3 tens and four ones = 34
3,531 = 11 + 220 + 3,300
265.99
2641.99
No tens. There are 3.6 ones.
4 tens + 9 ones 3 tens + 19 ones 2 tens + 29 ones 1 ten + 39 ones 49 ones.
8 tens 2 ones
Four tens and two ones.
For the number 25, the 5 is the ones digit (and the 2 is the tens digit). So, for 99 the second 9 from left to right is the ones digit.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }