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What is the equation of the straight line passing through the point 4 -2 and perpendicular to the line whose equation is 2x -y -5 equals 0?
2x-y -5 = 0 => y = 2x -5 The perpendicular slope is the negative reciprocal of 2 which is -1/2 So using the formula of y -y1 = m(x -x1) gives the straight line equation:- y - -2 = -1/2(x -4) y +2 = -1/2x +2 y = -1/2x +2 -2 y = -1/2x which can be expressed in the form of: x +2y = 0 So the straight line equation is: x +2y = 0
Graph the equation y -2x-4?
2
What are the solutions to the equation X2 plus 2x plus 2 equals 0?
x2 + 2x + 2 = 0 Use the quadratic formula: x = (-2 +- sqrt(4 - 8))/2 x = (-2 +- 2i)/2 = -1 +- i
What does y equals -2x-4 equal?
2
What is x2 4x 4?
(x2+3x-4) (x-4)
What is the solution of the equation x2-2x plus 4 equals 0?
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
What are the points of intersection of the curve and line of xy equals 4 and y equals 2x plus 2?
equation 1: xy = 4 equation 2: y = 2x+2 Substitute equation 2 into equation 1: x(2x+2) = 4 2x2+2x-4 = 0 => x = -2 or x = 1 When x = -2, y = -2 and when x = 1, y = 4 Therefore the coordinates are: (-2,-2) and (1,4)
Is x equals 4 for the problem 2x plus 4 equals 0?
Nope. In this case, x would be equal to -2. Here's how you can work it out: Given: 2x + 4 = 0 Subtract four from both sides of the equation: 2x + 4 - 4 = 0 - 4 2x = -4 Now divide both sides by two: 2x / 2 = -4 / 2 x = -2
Choose the equation of the line that contains the points 4 -4 and -2 0?
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
How do you find y intercept for -2x plus 2y equals 4?
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
What are at least 5 consecutive coordinates of the straight line equation 2x plus y -4 equals 0 on the Cartesian plane?
If: 2x+y-4 = 0 then y = -2x+4 Coordinates: (1, 2) (2, 0) (3, -2) (4, -4) (5, -6) and (6, -8)
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the straight line passing through the point 4 -2 and perpendicular to the line whose equation is 2x -y -5 equals 0?
2x-y -5 = 0 => y = 2x -5 The perpendicular slope is the negative reciprocal of 2 which is -1/2 So using the formula of y -y1 = m(x -x1) gives the straight line equation:- y - -2 = -1/2(x -4) y +2 = -1/2x +2 y = -1/2x +2 -2 y = -1/2x which can be expressed in the form of: x +2y = 0 So the straight line equation is: x +2y = 0
What is the peroendicular bisector equation of the given points -4 8 and 0 -2 in its general form with work shown?
Points: (-4, 8) and (0, -2) Midpoint: (-2, 3) Slope: -5/2 Perpendicular slope: 2/5 Perpendicular equation: y-3 = 2/5(x--2) => 5y-15 = 2x+4 => 5y = 2x+19 Therefore perpendicular bisector equation in its general form: 2x-5y+19 = 0
How many real solutions are there in the equation 2x2 plus 2x - 4 equals 0?
0 = 2x^2 + 2x - 4 = 2(x^2 + x - 2) = 2(x-1)(x+2) Thus, there are two real solutions: x = 1 and x = -2
What is the perpendicular bisector equation meeting the line segment of -4 8 and 0 -2?
2x -5y +19 = 0
What is the solution to the equation 2x plus 4 equals 8?
2x + 4 = 8Subtract 4 from each side of the equation:2x = 4Divide each side by 2:x = 2
