(x2+3x-4) (x-4)
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x2+4x+4=? this is a factoring equation, and the step by step equation is: 4x1=4 the factors of 4 that give me 4 are 2 and 2 because 2+2=4. x2+2x+2x+4 replace 4x with 2x+2x x(x+2)+2(x+2) factor out x2+2x and 2x+4 (x+4)(x+2) <-- your answer!!!!! XD
-2
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
y = x2 - 4x + 4 = (x - 2)2 has one repeated root
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)