They are two terms of an algebraic expression which can be arranged as : y-2a
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2a + a = 3a
If I've read your question correctly, you need to subtract: a2 +2a -7 a2 -4a2 +5a2 -6 = 2a2 -6 Note, if x - y = z, then y = x - z; so: 2a2 -6 - (a2 -2a +1) = 2a2 -6 - a2 +2a -1 = a2 +2a -7
(6ab + 9b)/(2a + 3) = 3b(2a + 3)/(2a + 3) = 3b
2a + 5a + 3a = 10a
3a + (3b - 2a) + 5b =3a + 3b - 2a + 5b =(3a - 2a) + (3b + 5b) =a + 8b