That's not even a question. It's only a statement that says that
some number is equal to itself.
2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).
Gathering like terms together, this is equal to 5a + 3b + 7c.
2a. (a, b and c are all equal.)
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
a+b+2+3=5+a+b
2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).
2ab - 6ac + 3b - 9c = b(2a + 3) - 3c(2a + 3) = (b - 3c)(2a + 3)
Gathering like terms together, this is equal to 5a + 3b + 7c.
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
2a + 2b = 26 2b + c = 22 ===> b = 11 - c/2 4c + 2b = 46 ===> b = 23 - 2c From the 2nd and 3rd equations: 11 - c/2 = 23 - 2c 22 - c = 46 - 4c 22 - 46 = -4c + c ===> -24 = -3c ===> c = 8 Substitute c=8 into the 3rd equation: b = 23 - 16 = 7 Substitute b=7 into the 1st equation: 2a + 14 = 26 2a = 12 ===> a = 6
A+c= 2a+b
2a. (a, b and c are all equal.)
2a*4b*(-3c) = ? 2 * 4 * -3 * a * b * c = ? -24abc
If ba = 2a + b , then find 23 + 32 +1
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
a+b+2+3=5+a+b
(2a + 3)(b - 3c)