so you are talking about 2x^2 - 11x + 14 ... So then you found the Common factor from the two pairs. Then you would do 2x^2 - 4x - 7x + 14. 2(x^2-2x) - (7x-2). If you rewrite it in factor form, then it would be (2x−7)(x−2). If you try to find what x is, then you would have two different sets now. 2x - 7 and x - 2. Move the number to the other side... 2x = 7 and x = 2. (2x = 7) = (x = 7/2).
Simply the equation: (2x−7)(x−2)
Solving for x: x = 7/2 or 2
14 squared = 196, so you're looking for the sqrt of double that, ie 392, which is almost exactly 19.8
34 minus 6
6
16
24 + 14 - 8 = ? According to BODMAS, 24 + 14 should be added first and then should be subtracted by 8. Thus, 24 + 14 = 38 38 - 8 = 30 The correct answer is 30.
(9x + 7)(x - 2)
It is: (x-2)(x-7) when factored
(x - 2)(2x + 7)
(y - 2)(y - 7)
If you mean 8+11x = -14 then the value of x works out as -2
2(x - 7)(x - 1)
-11x + 13
14 + 2x + 9x - 6 - 11x 14 - 6 + 2x + 9x - 11x The x values cancel themselves out, leaving just the number value The answer is therefore 8.
Distance travelled = 5x3 - 6x2 + 3x + 14 = 5x3 + 5x2 - 11x2 - 11x + 14x + 14 = 5x2(x + 1) - 11x(x + 1) + 14(x + 1) = (x + 1)(5x2 - 11x + 14) Then time = distance/rate = (x + 1)(5x2 - 11x + 14) / (x+1) = 5x2 - 11x + 14
It is: (g-5)(g-9)
You look for two integers which multiply to 33 and whose sum is 14 and these happen to be 11 and 3. So x^2 - 14x + 33 = x^2 - 3x - 11x + 33 =(x^2 - 3x) - (11x - 33) [sign for 33 changes because the bracket has a minus sign] =x * (x-3) + 11 * (x-3) =(x - 3) * (x - 11)
9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.