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so you are talking about 2x^2 - 11x + 14 ... So then you found the Common factor from the two pairs. Then you would do 2x^2 - 4x - 7x + 14. 2(x^2-2x) - (7x-2). If you rewrite it in factor form, then it would be (2x−7)(x−2). If you try to find what x is, then you would have two different sets now. 2x - 7 and x - 2. Move the number to the other side... 2x = 7 and x = 2. (2x = 7) = (x = 7/2).
Simply the equation: (2x−7)(x−2)
Solving for x: x = 7/2 or 2
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