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The product of four consective integers is one less than a perfect square?
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
How do you do this problem 15-3n equals n-1?
15-3n=n-1
What is 15 9 plus 3n?
Assume the expression is: 15 = 9 + 3n Subtract both sides by 9 to get: 15 - 9 = 9 - 9 + 3n 6 = 3n Finally, divide both sides by 3 to get: 6/3 = 3n/3 n = 2
What does 3n equals 15 plus 12 equal to?
3n = 15 + 12 = 27, 27/3 = 9 = n
The inequality is greater than 24?
-3(n-5)=24 -3n + 15 = 24 -3n= 24-15 -3n = 9 n=9/-3 n=-3
Two times a number plus five is three times a number?
2n+5 = 3n 5 = 3n-2n 5 = 1n check 2n+5 = 3n 2x5+5 = 3x5 10+5 = 15 15 = 15
What is the value of n in the equation 3n-6 equals 15?
73n-6+6=15+63n=213n/3=21/3n=7
What is 3n plus 15 equals?
3n + 15 equals 3 times the number n, the answer to which is increased by 15. It can only be evaluated if the value of n is known. The expression can be factorised but that is of marginal help in evaluating it.
What is 12-n4?
12-n4 = 8
What is 3 times a number plus 15 divided by 2?
(3n + 15) / 2
What is the nth term for 15 12 9 6?
3n
what is (3n)(3n-1)?
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
