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The second of two numbers is 4 times the first their sum is 45?
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them: * n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us: * n1 + 4n1 = 45 which gives us * n1 = 9. We can now use this solution to find n2 with the first equation * n2 = 4 n1 = 36 So the first number is 4, the second number is 36.
What does n1 sin 01 equals n2 sin 02 mean?
it is the formula of refraction. this is based of snell's law and its about the incident ray and the refracted ray. page 3 of this should be of help to you
What Addition Problem That Equals 122?
There are infinitely many possible answers. 1 + 121 is one possible answer.
What multiplication problem equals 17?
It is: 1*17 = 17 which is a prime number
How do you turn x-4y equals 11 in slope intercept form?
by just doing the problem
What is the Total number of orbitals in n equals 3?
n1 has 1 n2 has 4
Describe the sequence 25 26 24 27 23?
Well, well, well, looks like we're playing a little game of "let's mess with the numbers." This sequence seems to be jumping all over the place like a kangaroo on a sugar rush. Let's break it down: 25, 26, 24, 27, 23. Looks like each number is just doing its own thing, no rhyme or reason.
Codings for coprime number in c?
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
What is the pmf of trinomial distribution?
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
What is the common noun for the N1?
The N1 is a rocket.
The second of two numbers is 4 times the first their sum is 45?
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them: * n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us: * n1 + 4n1 = 45 which gives us * n1 = 9. We can now use this solution to find n2 with the first equation * n2 = 4 n1 = 36 So the first number is 4, the second number is 36.
Find LCM and HCF of two given number by using for loop in c?
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
What is the value of the expression n1?
the value of the exponent n1
What is the value of the expression of n1?
the value of the exponent n1
How can you create calculator in computer language cpp?
void main() { int i; float n1,n2; abc: printf("Enter two nos "); scanf("%f%f",&n1,&n2); printf("\n %f + %f = %f " ,n1,n2,n1+n2); printf("\n %f - %f = %f " ,n1,n2,n1-n2); printf("\n %f x %f = %f " ,n1,n2,n1*n2); printf("\n %f / %f = %f " ,n1,n2,n1/n2); printf("\npress 5 to make another calculation"); scanf("%d",&i); if (i==5) goto abc; }
What is the sum of the 10 positive integers?
The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55
What is the movie price at N1 City?
what are the price of a movie ticket at N1 city
