(6x)(5y)
(6x - 5y) + (-3x - 4y) =6x - 5y - 3x - 4y =3x - 9y =3 (x - 3y)
4x-2y
6x and 5y
6X + 5Y = 8 subtract 6X from both sides 5Y = -6X + 8 divide both sides by 5 Y = -6/5X+ 8/5 now you have a line of slope -6/5 that intersects the Y axis at 8/5. (Solve for X to get X intercept)
(6x)(5y)
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
(6x - 5y) + (-3x - 4y) =6x - 5y - 3x - 4y =3x - 9y =3 (x - 3y)
x= -1 y=-1
4x-2y
It's an algebraic expression that can be simplified to: x-5y
It is: x-5y simplified
It is: 6x-5y simplified
86
The question is not quite clear, do you mean -6x+3y = -18 and -10+5y = -30? If so then the solution is: -10+5y= -30 5y = -30+10 5y = -20 y = -4 Substitute the value of y into the equation -6x+3y = -18: Answer: x = 1 and y = -4
6x and 5y
6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.