f(x)=6x2+7x+2
f(x)=(6x+1)(x+2)
x= -1/6 and x= -2
The above answer is not correct. (6x+1)(x+2) yields 6x2+13x+2, not the original equation.
The answer can be arrived at using the quadratic equation, where ax2+bx+c=0 and
x=[-b (+-) square root(b2-4ac)] / 2a
x=[-7(+-) square root (72-4(6)(2))] / 2(6)
x=[-7(+-)square root(49-48)]/12
x=[-7(+-)1]/12
x=-1/2 and -2/3
7x + 2 = 6x + 2 if and only x = 0.
7x + 7 + 6x - 9 = 13x - 2
6x - 14 + 15x + 2 =21x - 12or3 (7x - 4)
7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1
what is 7x to the third power + 6x to the second - 2
7x + 2 = 6x + 2 if and only x = 0.
7x + 7 + 6x - 9 = 13x - 2
7x + 2
6x - 14 + 15x + 2 =21x - 12or3 (7x - 4)
7x + 2 = 158 - 6x7x + 2 + 6x = 158 - 6x + 6x13x + 2 - 2= 158 - 213x / 13 = 156/13x = 12
If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
5x2+ 7x + 2 = (x + 1)(5x + 2).
X=2
x=-7/13
(6x + 1)(x + 2)
Answer : 12
11