(6x + 1)(x + 2)
(x+13)(x+4)
-x2 + 11x + 26 = -(x - 13)(x + 2) = (13 - x)(x + 2) = (x - 13)(-x - 2)
There is no rational factorisation of 6y2 + 19y - 13 The roots are [-19 +/- sqrt(673)]/12 which are -3.74519 and 0.57852
13
4
13
(x+13)(x+4)
(6x + 1)(x + 13)
-x2 + 11x + 26 = -(x - 13)(x + 2) = (13 - x)(x + 2) = (x - 13)(-x - 2)
There is no rational factorisation of 6y2 + 19y - 13 The roots are [-19 +/- sqrt(673)]/12 which are -3.74519 and 0.57852
The factors of that trinomial are (x - 13) and (x + 3) . Neither of them appears below.
2^2 + 3^2 = 4 + 9 = 13
13
4
4
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 13) divided by 2x = 2.3027756377319946x = -1.3027756377319946
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes