well it could be anything, but I think you are thinking of Pythagoras' theorem.
a(2) x b(2) = c(2) (2) = squared
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
x = -c/(a+b), provided a+b is not 0
x = (d-a)/(a-c)
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
7.5
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
X= (b-c)/a
x = -c/(a+b), provided a+b is not 0
Only one. x = (c - b) / a
x = (c - b)/a in a deliberately complicated form!
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
x = (d-a)/(a-c)
Just got it-x=c+d-bKeep answering my own questions recently lol.
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.