The implied coefficient in front of ' K ' = 1
so,
1K + 9K
= 10K
----------
54
-98-4h+8k-40+k-9h = (-98-40)+(-4h-9h)+(8k+k) = -138-13h+9k
9k - 1 = k - 25 Subtract 1k from both sides: 8k - 1 = -25 Add 1 to both sides: 8k = -24 Divide both sides by 8: k = -24/8 = -3
Na+-K+ ATPase
no such thing
k(7k + 9)
k(9 - 5x)
That depends what the values of k and b are.
54
-98-4h+8k-40+k-9h = (-98-40)+(-4h-9h)+(8k+k) = -138-13h+9k
(k+3)/8 = 5/9 Cross Multiply: 9(k+3) = 5*8 Distribute: 9k+27 = 40 Subtract 27 from each side: 9k = 13 Divide each side by 9: k = 13/9
k=-2
It can be simplified to: 9k
9k + 8
35 + 2k = 9k subtract 2k from each side 35 + 2k - 2k = 9k - 2k 35 = 7k divide both sides integers by 7 35/7 = (7/7)k 5 = k check in original equation 35 + 2(5) = 9(5) 35 + 10 = 45 45 = 45 checks out
9k gold
9k - 1 = k - 25 Subtract 1k from both sides: 8k - 1 = -25 Add 1 to both sides: 8k = -24 Divide both sides by 8: k = -24/8 = -3