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35 + 2k = 9k
subtract 2k from each side
35 + 2k - 2k = 9k - 2k
35 = 7k
divide both sides integers by 7
35/7 = (7/7)k
5 = k
check in original equation
35 + 2(5) = 9(5)
35 + 10 = 45
45 = 45
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∙ 13y ago
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4k plus 3k plus 2k?
It can be simplified to: 9k
What does 9k plus 4b minus 7 minus 5k plus b equals?
That depends what the values of k and b are.
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54
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k=-2
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How do you find the product for this problem 3kminus6 times2k plus 1?
The question is unclear, so the author will provide answers for a number of interpretations: 1. 3k-6(2k+1) = 3k-12k-6=-9k-6=-3(3k+2) 2. 3k-6(2k)+1=3k-12k+1=-9k+1 3. (3k-6)(2k)+1 = 6k^2 -12k + 1 = 6(k-1-sqrt(5/6))(k-1+sqrt(5/6)) 4. (3k-6)(2k+1) = 6k^2 - 12k + 3k - 6 = 6k^2 -9k + 6 = 3(2k^2 - 3k + 2) Line 4 cannot be factorised further. sqrt and ^2 refer to the square root, and squared respectively. Lines 1 and 2 require knowledge of expansion of linear equations, addition of like terms, and factorisation of linear equations. Lines 3 and 4 also require knowledge of addition of like terms, and expansion and factorisation of quadratic equations. In no case can an exact value for k be determined as we were given an expression rather than an equality.
