b times 7
65
11 times. 11*7= 77
A. 7 B. 9 C. 13 D. 22
A
0.4286
a = b/7
The values of a and b are 7 and 18 or 18 and 7
2 and 7/100
top times top, bottom times bottom
The answer is 1 + 5v.
65
Let the shorter base be ( b ) and the longer base be ( 3b ). The height is given as the average of the two bases, which is ( \frac{b + 3b}{2} = 2b ). The area of the trapezoid is given by the formula ( \text{Area} = \frac{1}{2} \times (b + 3b) \times \text{height} ), leading to ( 112 = \frac{1}{2} \times 4b \times 2b ). Simplifying gives ( 112 = 4b^2 ), so ( b^2 = 28 ) and ( b = \sqrt{28} = 2\sqrt{7} ). Therefore, the longer base is ( 3b = 6\sqrt{7} ) yards.
seven times eight
1/a = 1/b: cross multiplying gives a = b
A. 7 B. 9 C. 13 D. 22
11 times. 11*7= 77
8ab/4c^7=2ab/c^7