Since x by itself is the same as 1x, the expression can be re-written as 1x+2x Then, ignore the x's and simply add the numbers to obtain 1x+2x=3x 3x is your answer.
x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
100x -1x = 99
It is -exp (-x) + C.
The antiderivative of 2x is x2.
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
x2 + 1x - 30 = (x + 6) (x - 5)
0.5 x2+C
For example, the derivate of x2 is 2x; then, an antiderivative of 2x is x2. That is to say, you need to find a function whose derivative is the given function. The antiderivative is also known as the indifinite integral. If you can find an antiderivative for a function, it is fairly easy to find the area under the curve of the original function - i.e., the definite integral.
x2-2x+C, where C is some arbitrary constant.
Since x by itself is the same as 1x, the expression can be re-written as 1x+2x Then, ignore the x's and simply add the numbers to obtain 1x+2x=3x 3x is your answer.
-1
the opposite of x or -x or -1x
9-1x=79-x=79-7=x2=xx=2
The antiderivative of x/(x2-1) is ln(x2-1)/2. Proof: (ln(x2-1)/2)' = (1/(x2-1))*(x2-1)'/2=1/(x2-1)*(2x/2)=x/(x2-1).
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)