x4 +x2 =x2 (x2+1)
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 12x + 27 = (x + 9)(x + 3)
The factors of x2 are x and x x times x plus 1 = x2 + x
x4 +x2 =x2 (x2+1)
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
(x2+10x+21)/(x+3) = (x+7)
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
(x2 - x + 1)(x2 + x + 1)
(x2 - x - 20) / (x2 + 8x + 16) = [(x - 5)(x + 4)] / (x + 4)2 = (x - 5) / (x + 4)
x2+36x+120 (x+6)(x+20)
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)