For it to be a right angle triangle the 3rd side must be 5cm
4cm x 5cm
area of a circle is pi x radius^2 so... pi x 4^2 = about 50 cm
Area of a rectangle = length x width If length = L and width = W, then Area = L x W For this case, the length is 4 cm longer than the width. Therefore, L = W + 4cm Replace length in the area equation at the top with this new L value: Area = (W + 4cm) x W Area = W^2 + (4cm) x W And area is 8 cm^2 (I assume you meant to say 8cm^2 is the area) Then: 8cm^2 = W^2 +4W This is a quadratic equation (because of the w^2 value), if you solve for W using the quadratic formula (Google it), you get W = 1.464cm Therefore, the length L = W + 4cm = 1.464cm + 4cm = 5.464cm Dimensions are L = 5.464cm and W = 1.464cm
Area: 54 square cm Perimeter: 30 cm
Area of a triangle = (1/2) x (base) x (height) Can you handle it from there ?
1/2*6*4 = 12 square cm
96 cm.^2
For it to be a right angle triangle the 3rd side must be 5cm
Assuming external area is the surface area. 2 x 6 x 4 = 48 sq cm (top and bottom area) 2 x 6 x 4 = 48 sq cm (two sides) 2 x 4 x 4 = 16 sq cm (two ends) 48 + 48 + 16 = 112 square centimetres is the total surface area.
4cm x 5cm
The volume of the cube is 4cm x 4cm x 4cm = 64 cm^3. To find the density, divide the mass (50g) by the volume (64 cm^3): density = 50g / 64 cm^3 β 0.78 g/cm^3.
Yes (apart from units):If the side of a square is 4cm then itsperimeter is 4cm + 4cm + 4cm + 4cm = 4 x 4cm = 16cm;area is 4cm x 4cm = 16cm2
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 7 cm and the width is 4 cm. Therefore, the area of the rectangle is 7 cm x 4 cm = 28 square cm.
That would have to be cubic cm. 216 of them.
Volume of a cuboid = widthxlengthxheight; therefore V = 2cm x 4cm x 1cm = 8cm3
area of a circle is pi x radius^2 so... pi x 4^2 = about 50 cm