Let the width be x -12 and length be x 2(x-12)+2(x) = 156 2x-24+2x = 156 2x+2x = 156 +24 4x = 180 x = 45 Therefore: width = 33cm and length = 45cm.
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
Area of triangle is 0.5*b*h where: b = base h = height thus Area is: 0.5*(4x-3)*(2x) = (4x-3)*(x) = 4x2 - 3x
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 x = 6 So: length = 24 and width = 6 Area = length*width Area = 144 square inches
Let the length be x+4 and the width be x: 2(length+width) = perimeter 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 x = 3 Therefore: length = 7 cm and the width = 3 cm Area = length*width = 7*3 = 21 square cm
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
Given the area, there is no justification for assuming that it refers to a rectangular area: it could be circular, triangular or an even irregular shape.However, if you make the totally unjustified assumption that it is a rectangle, then8x^2 + 2x - 3 = (4x + 3)*(2x - 1)Therefore the two lengths are 4x + 3 and 2x - 1.Conventionally, the length is the larger of the two sides and so, for positive solutions, the length is 4x + 3 units while the width is 2x - 1 units.
Let the length be 2x+7 and the width be x: 2(2x+7+x) = 62 4x+14+2x = 62 4x+2x = 62-14 6x = 48 x = 8 Therefore: length = 23 meters and width = 8 meters
Let the length be x-12 and the width be x: 2(length+width) = perimeter 2(x-12+x) = 240 2x-24+2x = 240 4x = 240+24 4x = 264 x = 66 Therefore: length = 54 feet and width = 66 feet
Presumably the question is about finding the dimensions of a rectangle? Let the length be 2x-3 and the width be x: 2(2x-3+x) = 36 4x-6+2x = 36 4x+2x = 36+6 6x = 42 x = 7 Therefore: length = 11 units and width = 7 units
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
If x was equal to 5 then the length would be 6 and the width would be 10 making the area = to 60 units. A = (2x-4) * (x+5) = 2x2 - 4x + 10x -20 = 2x2 +6x -20