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The width of a rectangle is 12 cm less than the length The perimeter is 156 cm Find the width and the length?
Let the width be x -12 and length be x 2(x-12)+2(x) = 156 2x-24+2x = 156 2x+2x = 156 +24 4x = 180 x = 45 Therefore: width = 33cm and length = 45cm.
The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
If the base is 4x-3 and the height is 2x what is the area of the triangle?
Area of triangle is 0.5*b*h where: b = base h = height thus Area is: 0.5*(4x-3)*(2x) = (4x-3)*(x) = 4x2 - 3x
How can you solve -2x equals -4x plus 24 step by step?
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
What the Anserw to 4x plus 1 equals 2x plus 5?
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
The length of a rectangle is twice its width If the perimeter of the rectangle is 60cm find its area?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cm what is the area of the rectangle?
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 inches. What is the area of the rectangle?
Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 x = 6 So: length = 24 and width = 6 Area = length*width Area = 144 square inches
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cms what is the area of the rectangle?
Let the length be x+4 and the width be x: 2(length+width) = perimeter 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 x = 3 Therefore: length = 7 cm and the width = 3 cm Area = length*width = 7*3 = 21 square cm
The length of a rectangle is 4cm longer than the width If the perimeter of the rectangle is 20 centimeters what is the area of the rectangle?
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
If the length of a certain rectangle is twice its width If the perimeter of the rectangle is 66 feet what are the length and the width?
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
How do you find the length and width when the area is 8x2 plus 2x-3?
Given the area, there is no justification for assuming that it refers to a rectangular area: it could be circular, triangular or an even irregular shape.However, if you make the totally unjustified assumption that it is a rectangle, then8x^2 + 2x - 3 = (4x + 3)*(2x - 1)Therefore the two lengths are 4x + 3 and 2x - 1.Conventionally, the length is the larger of the two sides and so, for positive solutions, the length is 4x + 3 units while the width is 2x - 1 units.
The perimeter of a rectangle is 62m the length is 7m more than twice the width find the dimensions?
Let the length be 2x+7 and the width be x: 2(2x+7+x) = 62 4x+14+2x = 62 4x+2x = 62-14 6x = 48 x = 8 Therefore: length = 23 meters and width = 8 meters
The perimeter of a rectangle is 240 feet and Its length is 12 less than it's width what are the dimensions of the rectangle?
Let the length be x-12 and the width be x: 2(length+width) = perimeter 2(x-12+x) = 240 2x-24+2x = 240 4x = 240+24 4x = 264 x = 66 Therefore: length = 54 feet and width = 66 feet
If the perimeter is 36 and the length is 3 less than twice the width?
Presumably the question is about finding the dimensions of a rectangle? Let the length be 2x-3 and the width be x: 2(2x-3+x) = 36 4x-6+2x = 36 4x+2x = 36+6 6x = 42 x = 7 Therefore: length = 11 units and width = 7 units
The length of a rectangle is twice its width If the perimeter is 84cm what are the dimensions of the rectangle?
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
A rectangle has a length 2 x - 4 and a width of x plus 5. What is the area of the rectangle in terms of x?
If x was equal to 5 then the length would be 6 and the width would be 10 making the area = to 60 units. A = (2x-4) * (x+5) = 2x2 - 4x + 10x -20 = 2x2 +6x -20
