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What is the area of a regular hexagon with an apothem of 16.5 yards long and a side 19 yards long rounded to the nearest tenth?
Wiki User
∙ 9y ago
16.5
Mercedes Gerlach
Wiki User
∙ 9y agoIf it is a regular hexagon, then it can be divided up into 6 equilateral triangles each of side 19 yards. Using Pythagoras, the height of those triangles is 19 x (√3)/2
→ area hexagon = 6 x 1/2 x 19 x (19 x (√3)/2) = 1083/2 √3 ≈ 937.9 sq yds (to 1 dp)
The apothem of the hexagon is 19 x (√3)/2 ≈ 16.454 = 16.5 rounded to 1 dp.
Area regular hexagon = 3 x side x apothem = 3 x 19 yd x 16.5 yd = 940.5 sq yd
This shows the importance of only rounding answers at the end, and if rounding must take place before the end, working with more digits than required for the answer so that it can be rounded with less loss of accuracy:
Working with the apothem to 2 dp:
area = 3 x 19 x 16.45 = 937.65 → 937.7 to 1 dp. (closer to the real area).
Working with the apothem to 3 dp gives:
area = 3 x 19 x 16.454 = 937.87 → 937.9 to 1 dp. (same to 1 dp)
Anonymous
1875.8
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