Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2.
Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]
9762
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
The area is about 127.3 square inches.
It is 665.1 sq inches.
9762
Perimeter of regular 6 sided hexagon: 6*7 = 42 inches
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
Each side is 8 inches.
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
The area is about 127.3 square inches.
See if the Hexagon is regular, that is, if all the sides are equal then the perimeter is 12inches x 6 as there are 6 sides for an hexagon. Therfore the answer is 72 inches.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
36 inches.
no the answer would be 13 because of this a hexagon has 6 sides so 78 divided by 6 equals 13 inches khizar (dont get it?)