The area of a square is calculated by multiplying the length of one side by itself. In this case, with sides of length 8, the area would be 8 x 8 = 64 square units.
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A square with sides of 8 cm will have an area of 64 square cm.
Area of the square: 8 times 8 = 64 square cm
8*sqrt(2) The diagonal of the square would be the hypotenuse of the right triangle formed by two of the sides of the square.
To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units. To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length. Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.
If the area of the square is 64 square cm then its sides are 8 cm. Its perimeter: 8+8+8+8 = 32 cm